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Question
Calculate the half-life of a first order reaction having a value of 2 × 10−3 s−1 for its rate constant.
Numerical
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Solution
Given:
First-order reaction
Rate constant: k = 2 × 10−3 s−1
By using half-life formula for a first-order reaction
`t_(1//2) = 0.693/k`
= `0.693/(2 xx 10^-3)`
= `0.693/0.02`
= 346.5 seconds
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