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Calculate the half-life of a first order reaction having a value of 2 × 10−3 s−1 for its rate constant. - Chemistry (Theory)

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प्रश्न

Calculate the half-life of a first order reaction having a value of 2 × 10−3 s−1 for its rate constant.

संख्यात्मक
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उत्तर

Given:

First-order reaction

Rate constant: k = 2 × 10−3 s−1

By using half-life formula for a first-order reaction

`t_(1//2) = 0.693/k`

= `0.693/(2 xx 10^-3)`

= `0.693/0.02`

= 346.5 seconds

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अध्याय 4: Chemical Kinetics - REVIEW EXERCISES [पृष्ठ २३७]

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नूतन Chemistry Part 1 and 2 [English] Class 12 ISC
अध्याय 4 Chemical Kinetics
REVIEW EXERCISES | Q 4.49 | पृष्ठ २३७
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