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Question
Calculate the equivalent conductance of 1 M H2SO4 solution, if its conductivity is 2.6 × 10−2 ohm−1 cm−1.
Numerical
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Solution
Given:
Conductivity κ = 2.6 × 10−2 S cm−1
Normality N = 2 N (since 1 M H2SO4 gives 2 equivalents per mole)
To calculate the equivalent conductance (Λeq) of a solution, use the formula:
`Lambda_"eq" = (kappa xx 1000)/N`
= `(2.6 xx 10^-2 xx 1000)/2`
= `26/2`
Λeq = 13 S cm2 eq−1
∴ The equivalent conductance of 1 M H2SO4 solution is 13 S cm2 eq−1
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