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Calculate: 3^5/3 × 2^−1/3 × 36^2/3 - Mathematics

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Question

Calculate:

`3^(5/3) xx 2^((-1)/3) xx 36^(2/3)`

Sum
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Solution

Given,

`3^(5/3) xx 2^((-1)/3) xx 36^(2/3)`

We need to simplify the given terms.

Thus, `3^(5/3) xx 2^((-1)/3) xx 36^(2/3)`

⇒ `3^(5/3) xx 2^((-1)/3) xx (6^2)^(2/3)`

⇒ `3^((6/3 + (-1)/3)) xx 2^((-1)/3) xx (6)^(2 xx 2/3)`

⇒  `3^(6/3) xx 3^((-1)/3) xx 2^((-1)/3) xx 6^(4/3)`...[∴ (am)n = amn]

⇒ `3^2 xx (3 xx 2)^((-1)/3) xx (6)^(4/3)`  ...[∴ an × bn = (ab)n]

⇒ `3^2 xx (6)^((-1)/3) xx (6)^(4/3)`

⇒ `3^2 xx (6)^((-1)/3 + 4/3)`   ...[∴ an × am = an + m]

⇒ 9 × 6 = 54

Hence, the required is 54.

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Chapter 6: Indices - EXERCISE 6 [Page 67]

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B Nirmala Shastry Mathematics [English] Class 9 ICSE
Chapter 6 Indices
EXERCISE 6 | Q 8. (iv) | Page 67
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