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Calculate: 25^−1/2 × 125^2/3 ÷ 625 - Mathematics

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Question

Calculate:

`25^((-1)/2) xx 125^(2/3) ÷ 625`

Sum
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Solution

Given,

`25^((-1)/2) xx 125^(2/3) ÷ 625`

We need to simplify the given terms.

Thus, `25^((-1)/2) xx 125^(2/3) ÷ 625`

⇒ `(5^2)^((-1)/2) xx (5^3)^(2/3) ÷ 5^4`

⇒ `(5)^(2 xx (-1)/2) xx (5)^(3 xx 2/3) ÷ 5^4`  ...[∴ (an)m = anm]

⇒ `(5)^-1 xx (5)^2 ÷ 5^4`

⇒ `(5)^(-1 + 2) ÷ 5^4`   ...[∴ an × am = an + m]

⇒ `(5)^1 ÷ 5^4`

⇒ `5^(1 - 4)`   ...[∴ an ÷ am = an – m]

= `5^-3`  ...`[∴ a^-n = 1/a^n]`

= `1/5^3`

= `1/125` 

Hence, the required is `1/125`.

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Chapter 6: Indices - EXERCISE 6 [Page 67]

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B Nirmala Shastry Mathematics [English] Class 9 ICSE
Chapter 6 Indices
EXERCISE 6 | Q 8. (vi) | Page 67
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