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Question
Calcualte the area under the curve y = `2sqrt(x)` included between the lines x = 0 and x = 1
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Solution
Given the curves y = `2sqrt(x)`, x = 0 and x = 1.
y = `2sqrt(x)`
⇒ y2 = 4x ......(Parabola)
Required area = `int_0^1 (2sqrt(x)) "d"x`
= `2 xx 2/3 [x^(3/2)]_0^1`
= `4/3 [(1)^(3/2) - 0]`
= `4/3` sq.units
Hence, required area = `4/3` sq.units
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