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Question
ΔАВC is reflected in origin to get ΔΑ'Β'C'.
Statement (1): ΔABC is congruent to ΔΑ'Β'C'.
Statement (2): The two triangles are similar to each other.
Options
Both the statements are true.
Both the statements are false.
Statement 1 is true, and statement 2 is false.
Statement 1 is false, and statement 2 is true.
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Solution
Both the statements are true.
Explanation:
When a point (x, y) is reflected across the origin, its image becomes (−x, −y).
So, under this transformation:
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All angles and side lengths are preserved.
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The orientation (clockwise/counter-clockwise) is reversed, but the size and shape remain identical.
According to statement 1: Δ ABC is congruent to Δ A'B'C' because in reflection lengths and angles are preserved.
So, statement 1 is true.
According to statement 2: Δ ABC is similar to Δ A'B'C' because all congruent triangles are similar.
So, statement 2 is true.
