Question

Bisector of ∠B of △ABC intersects side AC at point P, then point P is ______.

Options

• equidistant from vertices A and C

• PA = PB

• PB = PC

• equidistant from sides AB and BC

Answer 1

Bisector of ∠B of △ABC intersects side AC at point P, then point P is equidistant from sides AB and BC.

Explanation:

Given,

Bisector of angle B of triangle ABC intersects side AC at point P.

∴ P is equidistant from sides AB and BC.