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Question
Balance the following equation:
\[\ce{XeF6 + H2O -> XeO2F2 + HF}\]
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Solution
\[\ce{XeF6 + 2H2O → XeO2F2 + 4HF}\]
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| Column I | Column II |
| (A) XeF6 | (1) sp3d3 – distorted octahedral |
| (B) XeO3 | (2) sp3d2 – square planar |
| (C) XeOF4 | (3) sp3 – pyramidal |
| (D) XeF4 | (4) sp3d2 – square pyramidal |
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Match List - I with List - II:
| List - I | List - II | ||
| (Species) | (Number of lone pairs of electrons on the central atom) |
||
| (A) | XeF2 | (i) | 0 |
| (B) | XeO2F2 | (ii) | 1 |
| (C) | XeO3F2 | (iii) | 2 |
| (D) | XeF4 | (iv) | 3 |
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