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Question
Balance the following equation:
\[\ce{Al + H2SO4->Al2(SO4)3 + H2}\]
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Solution
\[\ce{Al + H2SO4->Al2(SO4)3 + H2}\]
To make atoms of Al and (SO4) equal
\[\ce{2Al + 3H2SO4->Al2(SO4) + H2}\]
To H atoms 6 multiply H2 on right by 3
\[\ce{2Al + 3H2SO4->Al2(SO4)3 + 3H2}\]
Atoms of each element on left are equal on the right side.
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