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Question
Balance the following equation:
\[\ce{Al + H2O->Al2O3 + H2}\]
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Solution
\[\ce{Al + H2O->Al2O3 + H2}\]
To balance Al and O atoms equal
\[\ce{2Al + 3H2O->Al2O3 + H2}\]
But there are 6 atoms of H on left and 2 atoms of H on right.
∴ \[\ce{2Al + 3H2O->Al2O3 + 3H2}\]
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