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Question
Balance the equation stepwise.
H2S2O7(l) + H2O(l) → H2SO4(l)
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Solution
H2S2O7(l) + H2O(l) → H2SO4(l)
Step 1: Count the number of each atom on the reactant side:
| Elements | No. of atoms in the reactant |
| H | 4 |
| S | 2 |
| O | 8 |
Step 2: Count the number of each atom on the product side:
| Elements | No. of atoms in the product |
| H | 2 |
| S | 1 |
| O | 4 |
Step 3: Number of atoms of elements on both side is not the same.
If we multiply the product side by 2, then the number of atoms in the product and reactant side gets balanced.
| Elements | No. of atoms in the reactant | No. of atoms in the product |
| H | 4 | 2 × 2 = 4 |
| S | 2 | 1 × 2 = 2 |
| O | 8 | 4 × 2 = 8 |
H2S2O7(l) + H2O(l) → 2H2SO4(l)
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