Question

At 90°C pure water has [H₃O⁺] = 10⁻⁶. What is the value of K_ω at this temperature?

Options

• 10⁻⁶

• 10⁻¹²

• 10⁻¹³

• 10⁻¹⁴

Answer 1

10⁻¹²

Explanation:

\[\ce{H2O <=> H^+ + OH^-}\]

K_h = `(["H"^+].["OH"^-])/(["H"_2"O"])`

K_ω = 10⁻¹²