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प्रश्न
At 90°C pure water has [H3O+] = 10−6. What is the value of Kω at this temperature?
पर्याय
10−6
10−12
10−13
10−14
MCQ
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उत्तर
10−12
Explanation:
\[\ce{H2O <=> H^+ + OH^-}\]
Kh = `(["H"^+].["OH"^-])/(["H"_2"O"])`
Kω = 10−12
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Ionic Equilibrium in Solution
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