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Assign oxidation number atom in the following species. Cr(OH)X4Θ

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Question

Assign oxidation number atom in the following species.

\[\ce{Cr(OH)^Θ_4}\]

Numerical
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Solution

\[\ce{Cr(OH)^Θ_4}\]

Oxidation number of O = –2

Oxidation number of H = +1

\[\ce{Cr(OH)^Θ_4}\] is an ionic species.

∴ Sum of the oxidation numbers of all atoms = – 1

∴ Oxidation number of Cr + 4 × (Oxidation number of O) + 4 × (Oxidation number of H) = – 1

∴ Oxidation number of Cr + 4 × (–2) + 4 × (+1) = – 1

∴ Oxidation number of Cr – 8 + 4 = – 1

∴ Oxidation number of Cr – 4 = – 1

∴ Oxidation number of Cr = – 1 + 4

∴ Oxidation number of Cr in \[\ce{Cr(OH)^Θ_4}\] = +3

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Chapter 6: Redox Reactions - Exercises [Page 92]

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Balbharati Chemistry [English] Standard 11 Maharashtra State Board
Chapter 6 Redox Reactions
Exercises | Q 3. (H)(a) | Page 92

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