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Assertion (A): The system of equations [2x - 3y - 5 = 0] and [4x - 6y + 3 = 0] has no solutions. Reason (R): The system of equations [a_{1}x+b_{1}y+c_{1}=0,\ a_{2}x+b_{2}y+c_{2}=0] has no solutions

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Question

Assertion (A): The system of equations \[2x-3y-5=0\] and \[4x-6y+3=0\] has no solutions.

Reason (R): The system of equations \[a_{1}x+b_{1}y+c_{1}=0,\ a_{2}x+b_{2}y+c_{2}=0\] has no solutions, if \[\frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}}\ne\frac{c_{1}}{c_{2}}.\]

Options

  • Both Assertion (A) and Reason (R) are true and Reason (R) is a correct explanation of Assertion (A).

  • Both Assertion (A) and Reason (R) are true but Reason (R) is not a correct explanation of Assertion (A).

  • Assertion (A) is true and Reason (R) is false.

  • Assertion (A) is false and Reason (R) is true.

MCQ
Assertion and Reasoning
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Solution

Both Assertion (A) and Reason (R) are true and Reason (R) is a correct explanation of Assertion (A).

Explanation:

Step 1 – Assertion: A is true. For the equations, \[\frac{a_{1}}{a_{2}}=\frac{2}{4}=\frac{1}{2},\quad \frac{b_{1}}{b_{2}}=\frac{-3}{-6}=\frac{1}{2},\quad \frac{c_{1}}{c_{2}}=\frac{-5}{3}.\] The first two ratios are equal but differ from the third, so the system has no solutions.

Step 2 – Reason: R is true. It states that the system has no solutions when the first two coefficient ratios are equal and differ from the third.

Step 3 – Link: The given equations satisfy this condition, so R correctly explains A.

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Chapter 20: Additional Questions - Linear Equations in Two Variables [Page 978]

APPEARS IN

R.S. Aggarwal Mathematics [English] Class 10
Chapter 20 Additional Questions
Linear Equations in Two Variables | Q 2. | Page 978
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