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Assertion (A): The sum of first 10 terms of the G.P. 3, 6, 9, 12, ... is 3096. Reason (R): The sum of first n-terms of a G.P. is given by $$S_{n} = \frac{a(r^{n} – 1)}{r – 1}$$.

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Question

Assertion (A): The sum of first 10 terms of the G.P. 3, 6, 9, 12, ... is 3096.

Reason (R): The sum of first n-terms of a G.P. is given by $$S_{n} = \frac{a(r^{n} - 1)}{r - 1}$$.

Options

  • Both A and R are true, and R is the correct explanation of A.

  • Both A and R are true, but R is not the correct explanation of A.

  • A is true, but R is false.

  • A is false, but R is true.

MCQ
Assertion and Reasoning
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Solution

A is false, but R is true.

Explanation:

Reason R is the correct formula for the sum of n terms of a G.P. when r > 1. But the sequence 3, 6, 9, 12, ... is an arithmetic progression, not a geometric progression, so the assertion is false.

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Chapter 11: Geometric Progression - COMPETENCY-FOCUSED QUESTIONS [Page 183]

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R.S. Aggarwal Mathematics [English] Class 10 ICSE
Chapter 11 Geometric Progression
COMPETENCY-FOCUSED QUESTIONS | Q 3. | Page 183
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