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Assertion (A): The next term of the AP $$\sqrt{3},\ \sqrt{12},\ \sqrt{27},\ \ldots$$ is $$\sqrt{48}.$$ Reason (R): In an AP, we have $$T_{n + 1} = (T_{n} + d).$$

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Question

Assertion (A): The next term of the AP $$\sqrt{3},\ \sqrt{12},\ \sqrt{27},\ \ldots$$ is $$\sqrt{48}.$$

Reason (R): In an AP, we have $$T_{n + 1} = (T_{n} + d).$$

Options

  • Both Assertion (A) and Reason (R) are true and Reason (R) is a correct explanation of Assertion (A).

  • Both Assertion (A) and Reason (R) are true but Reason (R) is not a correct explanation of Assertion (A).

  • Assertion (A) is true and Reason (R) is false.

  • Assertion (A) is false and Reason (R) is true.

MCQ
Assertion and Reasoning
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Solution

Both Assertion (A) and Reason (R) are true and Reason (R) is a correct explanation of Assertion (A).

Explanation:

Step 1 – Assertion: A is true. The terms simplify to $$\sqrt{3}, 2\sqrt{3}, 3\sqrt{3},$$ so the common difference is $$\sqrt{3}$$ and the next term is $$4\sqrt{3} = \sqrt{48}.$$

Step 2 – Reason: R is true. In an AP, the next term is obtained by adding the common difference to the current term.

Step 3 – Link: Adding the common difference $$\sqrt{3}$$ to the third term $$3\sqrt{3}$$ gives $$4\sqrt{3} = \sqrt{48},$$ so R correctly explains A.

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Chapter 20: Additional Questions - Arithmetic Progression [Page 994]

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R.S. Aggarwal Mathematics [English] Class 10
Chapter 20 Additional Questions
Arithmetic Progression | Q 8. | Page 994
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