Question

Assertion (A): In a frequency polygon, the frequencies are plotted against the mid value of the class intervals.

Reason (A): The mid value of a class is formed by `"upper limit + lower limit of the class"/2`

Options

• Both A and R are true and R is the correct reason for A.

• Both A and R are true but R is the incorrect reason for A.

• A is true but R is false.

• A is false but R is true.

Answer 1

Both A and R are true and R is the correct reason for A.

Explanation:

A frequency polygon plots frequencies against the mid-values (class marks) of each class interval. These mid-values are calculated by averaging the upper and lower limit of a class. After plotting the frequencies against these mid values, the points are joined to form the frequency polygon.