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Assertion (A): If a sector of a circle with central angle $$60^{\circ}$$ has an area $$924\ \text{cm}^{2}$$ then the radius of the circle is $$42\ \text{cm}$$. Reason (R): The sum of the areas

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Question

Assertion (A): If a sector of a circle with central angle $$60^{\circ}$$ has an area $$924\ \text{cm}^{2}$$ then the radius of the circle is $$42\ \text{cm}$$.

Reason (R): The sum of the areas of a major sector of a circle and its corresponding minor sector is equal to the area of the circle.

Options

  • Both Assertion (A) and Reason (R) are true and Reason (R) is a correct explanation of Assertion (A).

  • Both Assertion (A) and Reason (R) are true but Reason (R) is not a correct explanation of Assertion (А).

  • Assertion (A) is true and Reason (R) is false.

  • Assertion (A) is false and Reason (R) is true.

MCQ
Assertion and Reasoning
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Solution

Both Assertion (A) and Reason (R) are true but Reason (R) is not a correct explanation of Assertion (А).

Explanation:

Step 1 – Assertion: A is true. Using the sector-area formula, $$\pi r^{2}\times\frac{60}{360} = 924\ \text{cm}^{2}$$. With $$\pi = \frac{22}{7}$$, this gives $$r^{2} = 1764\ \text{cm}^{2}$$, so $$r = 42\ \text{cm}$$.

Step 2 – Reason: R is true. A major sector and its corresponding minor sector together make the whole circle.

Step 3 – Link: The reason describes the relationship between complementary sectors; it does not establish the radius from the given minor-sector area and angle.

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Chapter 20: Additional Questions - Area of Circle, Sector and Segment [Page 1037]

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R.S. Aggarwal Mathematics [English] Class 10
Chapter 20 Additional Questions
Area of Circle, Sector and Segment | Q 11. | Page 1037
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