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Assertion (A): From a bag containing 5 red balls, 2 white balls and 3 green balls, the probability of drawing a non-white ball is 4/5. Reason (R): For any event E, P(E) + P(not E) = 1. - Mathematics

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Question

Assertion (A): From a bag containing 5 red balls, 2 white balls and 3 green balls, the probability of drawing a non-white ball is `4/5`.

Reason (R): For any event E, P(E) + P(not E) = 1.

Options

  • Both, Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A).

  • Both, Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of Assertion (А).

  • Assertion (A) is true, but Reason (R) is false.

  • Assertion (A) is false, but Reason (R) is true.

MCQ
Assertion and Reasoning
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Solution

Both, Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A).

Explanation:

Assertion (A): Total number of balls = 5 (red) + 2 (white) + 3 (green) = 10

Number of non-white balls = 5 (red) + 3 (green) = 8

P(non-white) = `8/10 = 4/5`

So, Assertion (A) is true.

Reason (R): For any event E, the sum of the probability of the event and its complementary event is always 1.

`P(E) + P(barE) = 1`

So, Reason (R) is true.

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2025-2026 (March) Basic - 430/1/2
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