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Assertion (A) Consider the following frequency distribution: Class interval 3 – 6 6 – 9 9 – 12 12 – 15 15 – 18 18 – 21 Frequency 2 5 21 23 10 12 The mode of the above data is 12.4.

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Question

Assertion (A) Reason (R)
Consider the following frequency distribution:
Class
interval
3 – 6 6 – 9 9 – 12 12 – 15 15 – 18 18 – 21
Frequency 2 5 21 23 10 12

The mode of the above data is 12.4.

The value of the variable which occurs most often is the mode.

Options

  • Both Assertion (A) and Reason (R) are true and Reason (R) is a correct explanation of Assertion (A).

  • Both Assertion (A) and Reason (R) are true but Reason (R) is not a correct explanation of Assertion (A).

  • Assertion (A) is true and Reason (R) is false.

  • Assertion (A) is false and Reason (R) is true.

MCQ
Assertion and Reasoning
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Solution

Both Assertion (A) and Reason (R) are true but Reason (R) is not a correct explanation of Assertion (A).

Explanation:

Reason (R) is clearly true.

The maximum frequency is 23 and the modal class is 12 – 15.

∴ xk = 12, fk = 23, fk – 1 = 21, fk + 1 = 10 and h = 3.

∴ Mode = `{12 + 3 xx ((23 - 21))/((2 xx 23 - 21 - 10))}`

= `(12 + 3 xx 2/15)`

= 12.4

∴ Assertion (A) is true.

But, Reason (R) is not a correct explanation of Assertion (A).

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Chapter 18: Mean, Median, Mode of Grouped Data, Cumulative Frequency Graph and Ogive - MULTIPLE-CHOICE QUESTIONS (MCQ) [Page 904]

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R.S. Aggarwal Mathematics [English] Class 10
Chapter 18 Mean, Median, Mode of Grouped Data, Cumulative Frequency Graph and Ogive
MULTIPLE-CHOICE QUESTIONS (MCQ) | Q 31. | Page 904
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