Question

Assertion (A): A bag contains 5 red, 8 black and 7 green balls. One ball is drawn at random from the bag. The probability of getting neither a black nor a red ball is \[\frac{7}{20}\].

Reason (R): The total number of balls in the bag is 20, out of which 7 are neither black nor red.

Options

• Both Assertion (A) and Reason (R) are true and Reason (R) is a correct explanation of Assertion (A).

• Both Assertion (A) and Reason (R) are true but Reason (R) is not a correct explanation of Assertion (A).

• Assertion (A) is true and Reason (R) is false.

• Assertion (A) is false and Reason (R) is true.

Answer 1

Both Assertion (A) and Reason (R) are true and Reason (R) is a correct explanation of Assertion (A).

Explanation:

Step 1 – Assertion: A is true. Getting neither a black nor a red ball means drawing a green ball, so the probability is \[\frac{7}{20}.\]

Step 2 – Reason: R is true. There are 20 balls in total, of which 7 are green.

Step 3 – Link: R gives the total and favourable outcomes needed to obtain the probability in A.