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Question
Arrange the following ratios in ascending order of magnitude:
(2 : 3), (8 : 15), (11 : 12) and (7 : 16)
Sum
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Solution
L.C.M. of 3, 15, 12, 16 is 240:
$$\frac{2}{3} = \frac{160}{240}$$
$$\frac{8}{15} = \frac{128}{240}$$
$$\frac{11}{12} = \frac{220}{240}$$
$$\frac{7}{16} = \frac{105}{240}$$
Ascending order of numerators: $$105 < 128 < 160 < 220$$.
Ascending order: $$(7 : 16), (8 : 15), (2 : 3), (11 : 12)$$.
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Chapter 7: Ratio and Proportion - EXERCISE 7A [Page 95]
