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Arrange the following ratios in ascending order of magnitude: (2 : 3), (8 : 15), (11 : 12) and (7 : 16)

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Question

Arrange the following ratios in ascending order of magnitude: 

(2 : 3), (8 : 15), (11 : 12) and (7 : 16)

Sum
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Solution

L.C.M. of 3, 15, 12, 16 is 240:

$$\frac{2}{3} = \frac{160}{240}$$

$$\frac{8}{15} = \frac{128}{240}$$

$$\frac{11}{12} = \frac{220}{240}$$

$$\frac{7}{16} = \frac{105}{240}$$

Ascending order of numerators: $$105 < 128 < 160 < 220$$.

Ascending order: $$(7 : 16), (8 : 15), (2 : 3), (11 : 12)$$.

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Chapter 7: Ratio and Proportion - EXERCISE 7A [Page 95]

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R.S. Aggarwal Mathematics [English] Class 10 ICSE
Chapter 7 Ratio and Proportion
EXERCISE 7A | Q 39. (ii) | Page 95
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