English

Answer the following: How many six-digit telephone numbers can be formed if the first two digits are 45 and no digit can appear more than once?

Advertisements
Advertisements

Question

Answer the following:

How many six-digit telephone numbers can be formed if the first two digits are 45 and no digit can appear more than once?

Sum
Advertisements

Solution

Digits are 0, 1, 2, ... , 9 i.e., n = 10

The first two digits in each telephone number are 45.

∴ out of six-digit telephone numbers, only 4 digits from the remaining (10 – 2) = 8 digits are to be arranged.

Hence, the number of ways in which 6-digit telephone numbers can be formed

= 8P4

= 8 × 7 × 6 × 5

= 1680

shaalaa.com
  Is there an error in this question or solution?
Chapter 3: Permutations and Combination - Miscellaneous Exercise 3.2 [Page 68]

APPEARS IN

Balbharati Mathematics and Statistics 2 (Arts and Science) [English] Standard 11 Maharashtra State Board
Chapter 3 Permutations and Combination
Miscellaneous Exercise 3.2 | Q II. (13) | Page 68
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×