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An urn contains 10 black balls and 5 white balls. If \[E\] is the event “first ball is black,” what is \[P(E)\]?

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Question

An urn contains 10 black balls and 5 white balls. If \[E\] is the event “first ball is black,” what is \[P(E)\]?

Options

  • \[\frac{9}{14}\]

  • \[\frac{5}{15}\]

  • \[\frac{10}{15}\]

  • \[\frac{3}{7}\]

MCQ
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Solution

There are 10 black balls among 15 total balls. Therefore, the probability that the first ball is black is \[P(E)=\frac{10}{15}\].

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