Advertisements
Advertisements
Question
An urn contains 10 black balls and 5 white balls. If \[E\] is the event “first ball is black,” what is \[P(E)\]?
Options
\[\frac{9}{14}\]
\[\frac{5}{15}\]
\[\frac{10}{15}\]
\[\frac{3}{7}\]
MCQ
Advertisements
Solution
There are 10 black balls among 15 total balls. Therefore, the probability that the first ball is black is \[P(E)=\frac{10}{15}\].
shaalaa.com
Is there an error in this question or solution?
