Question

An observer stands at a certain distance away from a cliff and produces a loud sound. He hears the echo of the sound after 1.8 s. Calculate the distance between the cliff and the observer if the velocity of sound in air is 340 m−¹.

Answer 1

We know s = `"d"/"t"`

⇒ d = s × t

⇒ d = `340xx1.8/2`

∴ d = 306 m.