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Karnataka Board PUCPUC Science Class 11

An Object P Is Focussed by a Microscope M. A Glass Slab of Thickness 2.1 Cm is Introduced Between P And M. - Physics

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Question

An object P is focussed by a microscope MA glass slab of thickness 2.1 cm is introduced between P and M. If the refractive index of the slab is 1.5, by what distance should the microscope be shifted to focus the object again?

Sum
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Solution

Given,
Thickness of the glass slab, d = 2.1 cm
Refractive index, μ = 1.5
Shift due to the glass slab is given by,
\[∆ t = \left[ 1 - \left( \frac{1}{\mu} \right) \right]d\]
\[= \left[ 1 - \left( \frac{1}{1 . 5} \right) \right]\left( 2 . 1 \right)\]
\[= \frac{1}{3}\left( 2 . 1 \right) = 0 . 7  cm\]
Hence, the microscope should be shifted by 0.70 cm to focus the object 'P' again.

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Chapter 18: Geometrical Optics - Exercise [Page 413]

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HC Verma Concepts of Physics Vol. 1 [English] Class 11 and 12
Chapter 18 Geometrical Optics
Exercise | Q 17 | Page 413
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