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Question
An object is placed perpendicular to the principal axis of a convex lens of focal length 20 cm. If object is located at 30 cm from this lens, using lens formula find out the position and nature of the image formed.
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Solution
Given: Focal length (f) = +20 cm (positive for a convex lens)
Object distance (u) = −30 cm (Object is always placed to the left)
By using the lens formula:
`1/f = 1/v - 1/u`
`1/20 = 1/v - 1/-30`
`1/v = 1/20 - 1/30`
`1/v = 3/60 - 2/60`
`1/v = (3 - 2)/60`
`1/v = 1/60`
v = +60 cm
By using the formula for magnification:
m = `v/u`
= `60/-30`
= −2
The positive sign of v (+60 cm) indicates the image is formed on the opposite side of the lens, i.e., a real image is formed. The negative sign of m indicates the image is inverted. Since |m| > 1, the image is magnified (twice the size of the object).
