Department of Pre-University Education, KarnatakaPUC Karnataka Science Class 12
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An Inductor-coil Carries a Steady-state Current of 2.0 a When Connected Across an Ideal Battery of Emf 4.0 V. If Its Inductance is 1.0 H, Find the Time Constant of the Circuit. - Physics

Sum

An inductor-coil carries a steady-state current of 2.0 A when connected across an ideal battery of emf 4.0 V. If its inductance is 1.0 H, find the time constant of the circuit.

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Solution

We know that time constant is the ratio of the self-inductance (L) of the coil to the resistance (R) of the circuit.

Given:-

Current in the circuit, i = 2 A

Emf of the battery, E = 4 V

Self-inductance of the coil, L = 1 H

Now,

Resistance of the coil:-

\[R = \frac{E}{i} = \frac{4}{2} = 2 \Omega\]

Time constant:-

\[\tau = \frac{L}{R} = \frac{1}{2} = 0 . 5  s\]

Concept: Inductance - Self-Inductance
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APPEARS IN

HC Verma Class 11, Class 12 Concepts of Physics Vol. 2
Chapter 16 Electromagnetic Induction
Q 70 | Page 312
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