Department of Pre-University Education, KarnatakaPUC Karnataka Science Class 12

An Inductor-coil Carries a Steady-state Current of 2.0 a When Connected Across an Ideal Battery of Emf 4.0 V. If Its Inductance is 1.0 H, Find the Time Constant of the Circuit. - Physics

Sum

An inductor-coil carries a steady-state current of 2.0 A when connected across an ideal battery of emf 4.0 V. If its inductance is 1.0 H, find the time constant of the circuit.

Solution

We know that time constant is the ratio of the self-inductance (L) of the coil to the resistance (R) of the circuit.

Given:-

Current in the circuit, i = 2 A

Emf of the battery, E = 4 V

Self-inductance of the coil, L = 1 H

Now,

Resistance of the coil:-

$R = \frac{E}{i} = \frac{4}{2} = 2 \Omega$

Time constant:-

$\tau = \frac{L}{R} = \frac{1}{2} = 0 . 5 s$

Concept: Inductance - Self-Inductance
Is there an error in this question or solution?

APPEARS IN

HC Verma Class 11, Class 12 Concepts of Physics Vol. 2
Chapter 16 Electromagnetic Induction
Q 70 | Page 312