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An Inductor-coil Carries a Steady-state Current of 2.0 a When Connected Across an Ideal Battery of Emf 4.0 V. If Its Inductance is 1.0 H, Find the Time Constant of the Circuit.

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प्रश्न

An inductor-coil carries a steady-state current of 2.0 A when connected across an ideal battery of emf 4.0 V. If its inductance is 1.0 H, find the time constant of the circuit.

बेरीज
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उत्तर

We know that time constant is the ratio of the self-inductance (L) of the coil to the resistance (R) of the circuit.

Given:-

Current in the circuit, i = 2 A

Emf of the battery, E = 4 V

Self-inductance of the coil, L = 1 H

Now,

Resistance of the coil:-

\[R = \frac{E}{i} = \frac{4}{2} = 2 \Omega\]

Time constant:-

\[\tau = \frac{L}{R} = \frac{1}{2} = 0 . 5  s\]

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पाठ 38: Electromagnetic Induction - Exercises [पृष्ठ ३१२]

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एचसी वर्मा Concepts of Physics Volume 1 and 2 [English]
पाठ 38 Electromagnetic Induction
Exercises | Q 70 | पृष्ठ ३१२

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