English

An I0m Long Uniform Metallic Wire Having a Resistance of 20ω is Used as A Potentiometer Wire. this Wire is Connected in Series with Another Resistance of 480ω and a Battery of Emf 5v Having Negligible Internal Resistance. If an Unknown Emf E is Balanced Across 6m of the Potentiometer Wire, Calculate

Advertisements
Advertisements

Question

An I0m long uniform metallic wire having a resistance of 20Ω IS used as a  potentiometer wire. This wire is connected in series with another resistance of 480Ω
and a battery of emf 5V having negligible internal resistance. If an unknown emf e is balanced across 6m of the potentiometer wire, calculate

1) the potential gradient across the potentiometer wire

2) the value of the unknown emf e.

Advertisements

Solution

`l_1 = 10 m`

R = 20 Ω

`R_1 = 480 Ω`

V = 5 V

balancing lenght = `l_2  = 6m`

1) Potential gradient = `k = V/L = 5/6 = 0.83 "V/m"`

2) `E_1/E_2 - l_1/l_2`

`5/E_2 = 10/6`

`5 xx 6 = E_2 xx 10`

`(5 xx 6)/10 = E_2`

`:. E_2 = 3V`

shaalaa.com
  Is there an error in this question or solution?
2014-2015 (March)

APPEARS IN

RELATED QUESTIONS

In potentiometer experiment, if l1 is the balancing length for e.m.f. of cell of internal resistance r and l2 is the balancing length for its terminal potential difference when shunted with resistance R then :


A cell balances against a length of 200 cm on a potentiometer wire, when it is shunted by a resistance of 8Ω. The balancing length reduces by 40 cm, when it is shunted by a resistance of 4 Ω . Calculate the balancing length when the cell is in open circuit. Also calculate the internal resistance of the cell.


Why is it generally preferred to obtain the balance point in the middle of the meter bridge wire?


A resistance of R Ω draws current from a potentiometer as shown in the figure. The potentiometer has a total resistance Ro Ω. A voltage V is supplied to the potentiometer. Derive an expression for the voltage across R when the sliding contact is in the middle of the potentiometer.


(a) In a metre bridge [shown in the figure], the balance point is found to be at 39.5 cm from the end A, when the resistor Y is 12.5 Ω. Determine the resistance of X. Why are the connections between resistors in a Wheatstone or meter bridge made of thick copper strips?

(b) Determine the balance point of the bridge above if X and Y are interchanged.

(c) What happens if the galvanometer and cell are interchanged at the balance point of the bridge? Would the galvanometer show any current?


Write the principle of working of a metre bridge


In a meter bridge, the null point is found at a distance of l1 cm from A. If now a resistance of X is connected in parallel with S, the null point occurs at l2 cm. Obtain a formula for X in terms of l1l2 and S.


The figure shows experimental set up of a meter bridge. When the two unknown resistances X and Y are inserted, the null point D is obtained 40 cm from the end A. When a resistance of 10 Ω is connected in series with X, the null point shifts by 10 cm. Find the position of the null point when the 10 Ω resistance is instead connected in series with resistance ‘Y’. Determine the values of the resistances X and Y.


Two resistances are connected in the two gaps of a meter bridge. The balance points is 20 cm from the zero end. When resistance of 15 ohm is connected in series with the smaller of the two resistances, the null point shifts to 40 cm. The smaller of the two resistances has the value (in ohm) ______.


In meter bridge or Wheatstone bridge for measurement of resistance, the known and the unknown resistance are interchanged. The error so removed is ______.

Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×