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Question
An equilateral glass prism has a refractive index 1.6 in the air. Calculate the angle of minimum deviation of the prism, when kept in a medium of refractive index `4sqrt(2)"/"5.`
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Solution
When the prism is kept in another medium we have to take the refractive index of the prism with respect to the provided medium.
`"medium"^μ = ("μ"_"prism")/("μ"_"medium") = sin[((A + D_m)/2)]/sin(A/2)`
`1.6/((4sqrt(2))/5) = sin[((60^circ + D_m)/2)]/sin(60^circ/2)`
`sqrt(2) = sin[((60^circ + D_m)/2)]/(1/2)`
`sin^-1(1/sqrt(2)) = ((60^circ + D_m)/2)`
`90^circ = 60^circ + D_m`
`D_m = 30^circ`
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