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Question
An elevator descends into a mine shaft at the rate of 5 m/min. If the descent starts from 15 m above the ground level, how long will it take to reach −250 m?
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Solution
The elevator’s position = 15 m above ground level = +15 m
It should reach = −250 m
The distance to be travelled = 15 – (−250) m = 15 + 250 m = 265 m
Time taken to descend 5 m = 1 min
∴ Time required to descend 265 m = `24/8` = 53 min
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