Advertisements
Advertisements
Question
An element B shows valencies of 4 and 6. Write the formulae of its two oxides.
Advertisements
Solution
Case i
Valency of B = 4
Valency of O = 2
Elements : B O
Valencies : 4 2
Formula for the oxide formed by the element B (valency 4) can be worked out by crossing over the valencies of the constituent elements.
Therefore, formula of the oxide of element B is B2O4. The formula has a common factor of 2; hence, dividing the formula by the common factor gives us the simplest chemical formula: BO2.
Case ii
Valency of element B = 6
Valency of O = 2
Formula for the oxide formed by the element B (valency 6) can be worked out by crossing over the valencies of the constituent elements.
Therefore, formula of the oxide of element B is B2O6. The formula has a common factor of 2; therefore, dividing the formula by the common factor gives us the simplest chemical formula: BO3.
APPEARS IN
RELATED QUESTIONS
What do the symbols, H2, S and O4 mean in the formula H2SO4 ?
An element Y has a valency of 4. Write the formula for its :
- chloride
- oxide
- sulphate
- carbonate
- nitrate
Give the formula and valency of:
cupric ………………… .
Fill in the blank:
Formula of iron (ill) carbonate is _____ .
Name the element in the compound and give the formula of the following compound:
Nitric acid
Name the element in the compound and give the formula of the following compound:
Glauber’s salt
Write the formula of the following compound:
Zinc chloride
Write the formula of the following compound:
Copper [I] sulphide
Define the term Relative molecular mass. State why indirect methods are utilised to determine the absolute mass of an atom. Explain in brief the indirect method used.
State of the following formula of a compound is incorrect. Incorrectly write the correct formula.
KNO3
