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Karnataka Board PUCPUC Science 2nd PUC Class 12

An electron and a photon each have a wavelength of 1.00 nm. Find (a) their momenta, (b) the energy of the photon, and (c) the kinetic energy of electron.

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Question

An electron and a photon each have a wavelength of 1.00 nm. Find

(a) their momenta,

(b) the energy of the photon, and

(c) the kinetic energy of electron.

Numerical
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Solution

Wavelength of an electron (`lambda_"e"`) and a photon `(lambda_"p"), lambda_"e" = lambda_"p" = lambda` = 1 nm = 1 × 10−9 m

Planck’s constant, h = 6.63 × 10−34 Js

(a) The momentum of an elementary particle is given by de Broglie relation:

`lambda = "h"/"p"`

`"p" = "h"/lambda`

It is clear that momentum depends only on the wavelength of the particle. Since the wavelengths of an electron and a photon are equal, both have an equal momentum.

∴ p = `(6.63 xx 10^(-34))/(1 xx 10^(-9))`

= 6.63 × 10−25 kg ms−1

(b) The energy of a photon is given by the relation:

`"E" = "hc"/lambda`

Where,

Speed of light, c = 3 × 108 m/s

∴ E = `(6.63 xx 10^(-34) xx 3 xx 10^8)/(1 xx 10^(-9) xx 1.6 xx 10^(-19)`

= 1243.1 eV

= 1.243 keV

Therefore, the energy of the photon is 1.243 keV.

(c) The kinetic energy (K) of an electron having momentum p,is given by the relation:

`"K" = 1/2 "p"^2/"m"`

Where,

m = Mass of the electron = 9.1 × 10−31 kg

p = 6.63 × 10−25 kg ms−1

∴ K = `1/2 xx (6.63 xx 10^(-25))^2/(9.1 xx 10^(-31))`

= 2.415 × 10−19 J

= `(2.415 xx 10^(-19))/(1.6 xx  10^(-19))`

= 1.51 eV

Hence, the kinetic energy of the electron is 1.51 eV.

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Chapter 11: Dual Nature of Radiation and Matter - Exercise [Page 408]

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NCERT Physics Part I and II [English] Class 12
Chapter 11 Dual Nature of Radiation and Matter
Exercise | Q 11.16 | Page 408

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