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Question
An electron, a proton, a deuteron and an alpha particle are all accelerated from rest through the same potential difference. Which one will have the maximumde Broglie wavelength?
Options
Proton
Deuteron
Electron
Alpha particle
MCQ
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Solution
Electron
Explanation:
When a particle is accelerated through a potential difference (V), its de Broglie wavelength (λ) is calculated using:
λ = `h/p` = `h/sqrt(2 m q V)`
Since h (Planck’s constant) and V (potential difference) are the same for all the particles, the wavelength is inversely proportional to the square root of the product of mass (m) and charge (q):
`λ ∝ 1/sqrt(m q)`
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2025-2026 (March) Official Board Paper
