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Question
An electric pump is 60% efficient and is rated 2 HP. Calculate the maximum amount of water it can lift through a height of 5 m in 40 s.
[Take g = 10 ms−2 and 1 HP = 750 W]
Numerical
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Solution
Power of the pump = 2 × 750 = 1500 W
Useful power = 60% of 1500
= 0.60 × 1500
= 900 W
Useful work done in 40 s = power × time
= 900 × 40
= 36,000 J
This work lifts the water, so mgh = 36,000 J.
m × 10 × 5 = 36,000
m = `36000/50`
= 720 kg
Therefore, the maximum amount of water lifted is 720 kg.
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