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Question
An electric heater has a resistance of 40 Ω and draws a current of 4 A. Calculate : (a) its power (b) p.d. at its ends.
Numerical
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Solution
R = 40 Ω; I = 4 A; P = ?; V = ?
P = I2 × R
= (4)2 × 40
= 16 × 40
= 640 W
V = I × R
= 4 × 40
= 160 V
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