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Question
An electric heater draws a current of 4 A and its element has a resistance of 40 Ω. If the heater is switched on for 8 minutes, calculate the energy released in kilojoules.
Numerical
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Solution
I = 4 A; R = 40 Ω; t = 8 min = 480 s
∴ Energy released = I2 × R × t
= (4)2 × 40 × 480
= 307200 J
= 307.20 kJ
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