Advertisements
Advertisements
Question
An electric bulb is rated as 100W – 250V. What information does it convey? Calculate the resistance of its filament while glowing.
Advertisements
Solution
Given: P = 100 W, V = 250 volt
The resistance of filament, R = `"V"^2/"P" = (250)^2/100 = 625 Omega`
APPEARS IN
RELATED QUESTIONS
Which uses more energy, a 250 W TV set in 1 hr, or a 1200 W toaster in 10 minutes?
State two factors on which the electrical energy consumed by an electrical appliance depends.
Define kilowatt-hour.
Electrical power P is given by the expression P = (Q × V) ÷ time. What do the symbols Q and V represent?
An electric bulb is rated 250 W, 230 V. Calculate:
- the energy consumed in one hour
- the time in which the bulb will consume 1.0 kWh energy when connected to 230 V mains.
An electric kettle is rated 2.5 kW, 250 V. Find the cost of running the kettle for two hours at Rs. 5.40 per unit.
What is wrong with the circuit diagram (Fig. 34)? Carefully check the symbols and assign proper positive and negative signs to them.

An electric bulb is marked 100 W, 230 V. What does this mean?
An electric iron is rated at 230 V, 750 W. What is its resistance? What maximum current can be passed through it?
Out of the three fuses with current ratings 5A, 10A, 15A, which one is to be connected in a geyser circuit marked 3 kW, 220V? Give reason for your answer.
