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An alternating emf is applied to a series combination of an inductor and a resistor (R = 100 Ω ). If the impedance of the circuit is 1002 Ω, what is the phase difference between the emf and the cur

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Question

 An alternating emf is applied to a series combination of an inductor and a resistor (R = 100 Ω ). If the impedance of the circuit is `100 sqrt2  Ω`, what is the phase difference between the emf and the current?

Numerical
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Solution

Data: R = 100 Ω, Z = `100 sqrt2 Ω`

cos Φ = `R/Z`

= `100/(100sqrt2)`

= `1/sqrt2`

∴ `Φ = cos^-1 (1/sqrt2)`

= π/4 rad

= 45°

This is the phase difference between the emf and the current.

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