Question

An alkyl bromide (A) reacts with sodium in ether to form 4, 5 – diethyloctane, the compound (A) is

Options

• CH₃(CH₂)₃Br

• CH₃(CH₂)₅Br

• CH₃(CH₂)₃ CH(Br)CH₃

• \[\begin{array}{cc}\ce{CH3 - (CH2)2 - CH(Br) - CH2}\\\phantom{.........................}|\\
  \phantom{............................}\ce{CH3}
  \end{array}\]

Answer 1

\[\begin{array}{cc}\ce{CH3 - (CH2)2 - CH(Br) - CH2}\\\phantom{.........................}|\\
\phantom{............................}\ce{CH3}
\end{array}\]