Question

An alkene “A” on reaction with O₃ and Zn – H₂O gives propanone and ethanol in equimolar ratio. Addition of HCl to alkene “A” gives “B” as the major product. The structure of product “B” is

Options

• \[\begin{array}{cc}
  \phantom{....................}\ce{CH3}\\
  \phantom{.................}|\\
  \ce{Cl - CH2 - CH2 - CH}\\
  \phantom{.................}|\\
  \phantom{....................}\ce{CH3}
  \end{array}\]

• \[\begin{array}{cc}
  \phantom{..........}\ce{CH2Cl}\\
  \phantom{.....}|\\
  \ce{H3C - CH2 - CH - CH3}
  \end{array}\]

• \[\begin{array}{cc}
  \phantom{.........}\ce{CH3}\\
  \phantom{.......}|\\
  \ce{H3C - CH2 - C - CH3}\\
  \phantom{.......}|\\
  \phantom{........}\ce{Cl}
  \end{array}\]

• \[\begin{array}{cc}
  \phantom{..............}\ce{CH3}\\
  \phantom{............}|\\
  \ce{H3C - CH - CH}\\
  \phantom{............}|\\
  \phantom{............}\ce{Cl}
  \end{array}\]

Answer 1

\[\begin{array}{cc}
\phantom{.........}\ce{CH3}\\
\phantom{.......}|\\
\ce{H3C - CH2 - C - CH3}\\
\phantom{.......}|\\
\phantom{........}\ce{Cl}
\end{array}\]