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Question
An AC source is connected to a capacitor C. Due to decrease in its operating frequency ______.
Options
displacement current increases.
displacement current decreases.
capacitive reactance remains constant
capacitive reactance decreases.
MCQ
Fill in the Blanks
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Solution
An AC source is connected to a capacitor C. Due to decrease in its operating frequency displacement current decreases.
Explanation:
Displacement current (Ip) = Conduction current (Ic)
\[I_{D}=I_{C}=\frac{V}{X_{c}}\], where Xc = Capacitive reactance.
Xc = \[\frac {1}{ωC}\], where, ω = angular frequency and
C = capacitance.
ω = 2πf, where f = frequency,
When f decreases, ω decreases, them Xc increases, so IC or ID decreses.
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