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All oranges have equal weight. The two papayas have the same weight. The weights in the first and second balances are equal. How many oranges balance the weight in the third?

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Question

All oranges have equal weight. The two papayas have the same weight. The weights in the first and second balances are equal.

How many oranges balance the weight in the third?

Sum
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Solution

In first balance-
1 Mango + 1 orange = 3 orange
Therefore, 1 mango = 3 orange – 1 orange
= 2 orange

In second balance,
2 papaya = 2 orange + 1 mango
= 2 orange + 2 orange (Because 1 mango = 2 orange)
= 4 orange

Therefore, 1 papaya = 2
orange In third balance,
1 papaya + 1 mango = 2 orange + 2 orange (Because 1 papaya = 2 orange and 1 mango = 2 orange)
= 4 orange.

Hence, 4 oranges will balance the one papaya and together with one mango in third balance.

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How Heavy? How Light?
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Chapter 12: How Heavy? How Light? - Exercises [Page 148]

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NCERT Math - Magic [English] Class 4
Chapter 12 How Heavy? How Light?
Exercises | Q 29 | Page 148

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