Question

According to Coulomb's law, which is the correct relation for the following figure?

Options

• q₁q₂ > 0

• q₁q₂ < 0

• q₁q₂ = 0

• 1 > q₁/q₂ > 0

Answer 1

q₁q₂ < 0

Explanation:

According to Coulomb's law, `vecF_12 = - vecF_21`

There is a force of attraction and the charge must be unlike the charge.

And we know that F = `(q_1q_2)/(4πε_0r^2)`

For attractive force, q₁q₂ < 0

q₁ = +

q₂ = –

q₁q₂ < 0