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प्रश्न
According to Coulomb's law, which is the correct relation for the following figure?
पर्याय
q1q2 > 0
q1q2 < 0
q1q2 = 0
1 > q1/q2 > 0
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उत्तर
q1q2 < 0
Explanation:
According to Coulomb's law, `vecF_12 = - vecF_21`
There is a force of attraction and the charge must be unlike the charge.
And we know that F = `(q_1q_2)/(4πε_0r^2)`
For attractive force, q1q2 < 0
q1 = +
q2 = –
q1q2 < 0
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