Question

ΔABC ~ ΔPQR, A(ΔABC) = 80 sq.cm, A(ΔPQR) = 125 sq.cm, then complete `(A(ΔABC))/(A(ΔPQR)) = 80/125 = (square)/(square)`, hence `(AB)/(PQ) = (square)/(square)`

Answer 1

`(A(ΔABC))/(A(ΔPQR)) = 80/125` = \[\frac{{\boxed{16}}}{{\boxed{25}}}\]   ...(i)[Given]

`(A(ΔABC))/(A(ΔPQR)) = (AB^2)/(PQ^2)`   ...(ii)[Theorem of areas of similar triangles]

∴ `(AB^2)/(PQ^2) = 16/25`   ...[From (i) and (ii)]

Hence `(AB)/(PQ)` = \[\frac{{\boxed{4}}}{{\boxed{5}}}\]   ...[Taking square root of both sides]