Question

AB is a pole of height  6 m standing at a point  B and CD is a ladder inclined at angle of 60⁰ to the horizontal and reaches upto a point D of pole . If AD = 2.54 m , find the length of the ladder.    

Answer 1

In the given figure,
AB = AD + DB = 6 m
Given: AD = 2.54 m
⇒ 2.54 m + DB = 6 m
⇒ DB = 3.46 m

Now, in the right triangle BCD,

`(BD)/(CD)=sin 60°` 

`⇒ (3.46 m)/(CD)=sqrt3/2`

`⇒(3.46 m)/(CD)=1.73/2`

`⇒ CD= (2xx3.46m)/1.73`

`⇒ CD=4 m`

Thus, the length of the ladder CD is 4 m.